When you are dealing with mass-mass calculations you will always have the expected value and your value. By doing this you are able to use both of these values to calculate your deviation and percent loss in the easiest way I have been taught. I however think that when using mass-mass calculations there is a risk for error. When you make a mass-mass calculation you do them one step at a time. Then when proceeding to the next step you will use your previous value that you have just found and plug it into your next equation. I think that by using a process like this one, you have a very high chance of error. All you have to do is make one miscalculation or transfer of a nu

mber from a equation to another and it will ruin the whole problem. Instead of only having to make one correction you would most likely have to redo the problem because of the step by step process it would affect the whole problem.

Now, when you take the difference of the deviation in table 2 and subtract I from the deviation from table 1 you will get -. 28. Then by taking this number you it make equal to the difference of the table 1's actual mass alum and table 2's actual mass alum, which is also -. 28. By solving algebraically that is not to hard to do for this problem, you figure out that whatever happens to the deviation, the exact same effect will happen to the actual mass alum.

When you compare the results of table 1 and table 2 you will find some differences. In table 1, the %yield is 7.56 x 10^1 and table 2, the %yield is 7.67 x 10^1. Then when you look at the actual mass alum in table 1 it is 19.95g of alum and in table 2 it is 20.23g of alum. Therefore concluding that the higher your yield is the mass of the alum w

Some common words found in the essay are:
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Approximate Word count = 698
Approximate Pages = 3 (250 words per page double spaced)